package com.linkai.多线程._06_syn;

/**
 * @Description: 死锁：多个线程相互抱着对方需要的资源，然后形成僵持
 * @Author: 林凯
 * @Date: 2021/10/19 23:06
 */
public class DeadLock {
    public static void main(String[] args) {
        Makeup g1 = new Makeup(0, "A");
        Makeup g2 = new Makeup(1, "B");

        g1.start();
        g2.start();

    }
}

// 口红
class Lipstick{
}

// 镜子
class Mirror{
}

class Makeup extends Thread {
    // 需要的资源只有1分，用 static 来保证只有1分
    static Lipstick lipstick = new Lipstick();
    static Mirror mirror = new Mirror();

    int choice; // 选择
    String girlName;    // 使用化妆品的人

    public Makeup (int choice, String girlName) {
        this.choice = choice;
        this.girlName = girlName;
    }

    @Override
    public void run() {
        // 化妆
        try {
            makeup();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }

    // 化妆：互相持有对方的锁，就是需要拿到对方的资源
    private void makeup() throws InterruptedException {
        if (choice == 0) {
            synchronized (lipstick) {   // 获得口红的锁
                System.out.println(this.getName() + "获得口红的锁");
                Thread.sleep(1000);
                // 放在前面的同步块内部，模拟请求保持
                synchronized (mirror) {     // 1秒钟后获得镜子的锁
                    System.out.println(this.getName() + "获得镜子的锁");
                }
            }

        } else {
            synchronized (mirror) {     // 获得镜子的锁
                System.out.println(this.getName() + "获得镜子的锁");
                Thread.sleep(1000);
                synchronized (lipstick) {     // 1秒钟后获得口红的锁
                    System.out.println(this.getName() + "获得口红的锁");
                }
            }
        }

    }
}
